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A 1979 IIT Question
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to find the minimum value of an expression , differentiate it and then equate it to zero. here in this case, d/dx{(a+x)(b+x)/c+x}=0 => (c+x)(a+b+2x)-[ab+(a+b)x+x2]/(c+x)2 = 0 => x2+2cx+ca+cb-ab=0 =>x=-2c+2[ ]  c2-(ca+cb-ab)/2 {since x>-c}substituting in the given expression and simplifying we get, =([ ]
a-c + [ ]b-c)2 |
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