I am explaining by taking example 3x3 matrix
Adjoint of Matrix :
Adjoint or Adjugate Matrix of a square matrix is the transpose of the matrix formed by the cofactors of elements of determinant |A|.
To calculate adjoint of matrix we have to follow the procedure
a) Calculate Minor for each element of the matrix.
b) Form Cofactor matrix from the minors calculated.
c) Form Adjoint from cofactor matrix.
For an example we will use a matrix A
| Matrix A | = | | a11 | a12 | a13 | | a21 | a22 | a23 | | a31 | a32 | a33 | |
Step 1: Calculate Minor for each element.
To calculate the minor for an element we have to use the elements that do not fall in the same row and column of the minor element.
| Minor of a11 = M11 | = | | a11 | a12 | a13 | | a21 | a22 | a23 | | a31 | a32 | a33 | | = | | = | a22xa33 - a32xa23 |
| Minor of a12 = M12 | = | | a11 | a12 | a13 | | a21 | a22 | a23 | | a31 | a32 | a33 | | = | | = | a21xa33 - a31xa23 |
| Minor of a13 = M13 | = | | a11 | a12 | a13 | | a21 | a22 | a23 | | a31 | a32 | a33 | | = | | = | a21xa32 - a31xa22 |
| Minor of a21 = M21 | = | | a11 | a12 | a13 | | a21 | a22 | a23 | | a31 | a32 | a33 | | = | | = | a12xa33 - a32xa13 |
Similarly M22 = a11xa33 - a31xa13 M23 = a11xa32 - a31xa12 M31 = a12xa23 - a22xa13 M32 = a11xa23 - a21xa13 M33 = a11xa22 - a21xa12 |
| Example: | Find the adjoint of the following matrix: |
| Solution: | First find the cofactor of each element. Finally the adjoint of A is the transpose of the cofactor matrix: |