As we know for constant acceleration a, x = v0(t) + (1/2)a(t)2x /t= v0 + (1/2)a(t)vav = = v0 + (1/2)a(t) v = a(t)t = v/a Substituting the value of t in the second term of the first equation vav = v0 + (1/2)a(v/a) = v0 + (1/2)(v - v0) vav = (1/2)(v + v0) As can be seen this result is derived from the results for constant acceleration. It isn't applicable to non uniform accelerations.