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Discussion Response Post to: no of equations

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26 Jan 2007 21:26:57 IST

Subject: Re:no of equations

rahul_c (188)

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p = [ (x^3) +2]/x

for maximum value of p dp/dx = 0

3 (x^3) - (x^3) -2 =0

which gives x= 1

therefore maximum value of p= 3

f(x) = x^3 -px +2

for real roots p should be greater than 0

number of values of p 1,2,3

hence number of equations is 3

The yardstick of human intelligence is the ability to overcome the last fallacy

this reply: 2 points (with 0 Olaaa!! Perrrfect answer.

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