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trigno.. plz help and have a salute
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| Forum Index -> Analytical Geometry -> View Full Question |
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sec # + tan # = p => 1/cos # + sin # /cos # = p =>(1+ sin #) / cos# = p => (1 + sin #)^2 / cos ^ 2 # = p^2 =>(1 + sin #)/ (1-sin #)=p^2 [cos ^ # = 1-sin ^ 2 # = (1+ sin #)(1-sin #)] =>sin # (1+p^2)=p^2-1 sin # = (p^2-1)/ (1+p^2) |
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NIT silchar electrical engineering |
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