Prove your wisdom in Rotaional dynamics
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The bottommost point slips backwards. So friction acts forward with its max value 5 (Assuming g = 10). The acceleartion is |
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. The net torque is 95, so the angular accelerations
. The velocity of the centre is then
and angular velocity of the disk at any time is
. Here
is never possible. So, friction will keep on acting and the point of contact will keep on slipping. The work done is 








