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Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: trigonometric equations&inverse trigonometric ratios.
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puneet (3588)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 624  bad job dude!! I dont approve of this answer! 2  [862 rates]

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total posts: 1966    
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hiiiii
 
we at goIIT answer only one query at one time ..
 
I am also not sure about the (2) question .. i donno wat it means ..
 
well .. for the fisrt one ..
 
 
sin3x + cos4x - 4sin7x = cos10x + sin17x
 
or, sin3x - sin17x - 4sin7x = cos10x - cos4x
 
or, -2sin7x.cos10x - 4sin7x = -2sin3x.sin7x
 
or,  sin7x( cos10x - sin7x + 2) = 0   
 
so, either sin7x = 0 or cos10x - sin7x + 2 = 0
 
if sin7x = 0 .. this means x = 0 , /7 , 2/7 , 3/7 , 4/7 , 5/7 , 6/7 ,  
 
else if cos10x - sin7x + 2 = 0
 
this clearly means that sin7x = 1 and cos10x = -1 which is not possible ..
 
Thus the solution is x = 0 , /7 , 2/7 , 3/7 , 4/7 , 5/7 , 6/7 ,
 
cheers
 

Puneet Agrawal
IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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