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[Post New]26 Jan 2007 22:29:41 IST
    Subject: solve it if u can
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gorakavipraveen (121)

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Olaaa!! Perrrfect answer. 19  bad job dude!! I dont approve of this answer! 1  [34 rates]
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Its easy, infact
look g(x^2)=p[x^2+x+1] and g(w^4)=g(w)=p*0=0
and for h(x^2)*x^2=q[x^2+x+1] and substitue w^2 for x to get the result.

I mea omega for w friend. I think you understood. SO ANSWERE IS A .
Praveen kumar gorakavi
Hyderabad.
gorakavipraveen@gmail.com
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