inverese from bansal
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general term is cot-1(n2+3/4) or tan-1(1/ n2+3/4) Now write n2+3/4 as (n2-1/4)+1 or (n+1/2)(n-1/2) +1 Hence the genral term becomes tan-1(n+1/2) - tan-1(n-1/2) the answer becomes pi/2 - tan-11/2 |
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