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A block of mass 2 kg rests on a rough horizontal plank, the coefficient of friction between
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Fr=K*N; K=coefficient of friction.... N=Normal Force.... a (due to fr)= - 0.3*2*10/2 the block is in contact with the plank hence it should tend to move wid 4 m/s2 but Fr reduces the value of acc to 1(4-3) thus using s = 1/2 a*(tsquare) ans=8m... Hope this helps..... Please do rate |
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