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nikhila1234 (336)

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NaNO3+H2SO4 ---->  NaHSO4 + HNO3

6FeSO4 + 2 HNO3 + 3H2SO4 -----> 3Fe2(SO4)3 + 4H2O + 2NO
 
[Fe(H2O)6]SO4.H2O + NO -----> [Fe(H2O)5NO]SO4 + 2H2O
                                                   (Brown ring)

NO indeed replaces a water ligand, but by doing so, it is oxidized to a nitrosyl ligand, NO+. So, you get the compound [Fe(H2O)5NO]2+, but in this compound there is no NO ligand, but a NO+ ligand. The iron has oxidation state +1 in this complex, which is quite remarkable! Normally, iron has oxidation state +2 or +3.

On dilution, the nitrosyl complex is destroyed. It hydrolyses. The NO+ entity is not stable in water and is quickly converted to NO2- and/or HNO2. Iron in oxidation state +1 is not stable in water and so, the nitrite is reduced to gaseous NO.

Nikhila
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