Consider an element making an angle with the diameter of the half ring and subtending d at its center. Charge on the element dq = (q/R)Rd = (q/)d Electric field at the center due to this element dE = (1/4)(dq/R2) = (1/4)[(q/)d/ R2] E = dE sin = (q/42R2)0pi sind E = q/22R2
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410
with the diameter of the half ring and subtending d
at its center.
R)Rd
)(dq/R2) = (1/4
dE sin
= (q/4
R2
