RHL for rhl, |1-x|=x-1 thus limit is 1/(approaching 0+) =infinity
LHL for lhl, |1-x|=1-x limit is 1/(approaching 0 +) =infinity
U can also observe from its graph that x=1 is a vertical asymptote and the function is always +ve...so approaching to 1 from either side will give the limiting value of y as infinity.
Moderation Team
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