sign up I login
 advanced
» win an I-Phone. check i-points

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: electricity (gauss law)
Forum Index -> Electricity -> View Full Question like the article? email it to a friend.  
Author Message
sulekha_hi (39)

Cool goIITian

Olaaa!! Perrrfect answer. 7  [9 rates]

sulekha_hi's Avatar

total posts: 79    
offline Offline
Find the flux of the electric field thruogh a spherical surface of radius R due to a charge of 10 to the power -7 at the center and another equal charge at a point 2R away from the center.
          
b) A charge  q is placed at the center of the open cylindrical vessel. the flux of electric field through the surface of the vessel is q/2 how can this be true. the two surfaces are not parallel plate conductor.

Be like a postage stamp.Stick to anything until you get there.
Sulekha
    
 

 Aakash Institute IIT/ AIEEE/ Medical Crash Course
Name  
E-mail  
Phone  
Mobile  
** Hurry. Exclusive goIIT Offer. Limited Seats Only!
available in: New Delhi, Amritsar, Bhatinda, Bokaro, Chandigarj, Dehradun, Guwhati, Hyderabad, Indore, Jaipur, Kanpur, Karnal, Kolkata, Kota, Lucknow, Ludhiana, Mumbai, Noida, Patiala, Patna, Pune, Ranchi, Varanasi
Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Aakash-IITJEE : AIEEE
Aakash-IITJEE : DCE
Aakash-IITJEE : MHTCET
Aakash Institute : AIPMT
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya