since the net force is 350N... the bottom point is NOT hinged and the body undergoes both rotation and translation...ok in the frame of center of mass.. the net torque acting=500x2 clockwise - 350x4 anti clockwise.. =400Nm clockwise... but I= therefore =/I=(400*12/50*82)=3/2...therefore in center of mass frame the acc of top most point is 4x(3/2)=6 m/s2against the direction of the force ...now with respect to ground frame.. the center of mass has a acc of 350/50=7m/s2 in the direction of the force therefore the net acc =7-6=1m/s2 in the direction of the force.. if im wrong someone PLZ point out..
Moderation Team
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92
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therefore 
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