IIT JEE , AIEEE Forum - Physics , Electricity

akumar_ak

a) electric flux = q/epsilon naught

b)if a dipole is enclosed by a cosed surfacxe,flux =0
hence the algbraic sum of charges (+q-q) = 0

c)flux will come out of +ve charge is enlcosed,vice versa

d)flux from a cube :

i)if q is at the centre of cube,total flux = q/ep

ii)from each surface of cube,flux = q/6ep

e)electric field due to a charged shell = Q/4pieepr^2
here,the shell behaves like a pint charges

at a point on surface of shell : this is Emax.
E = Q/4pie*ep*r^2

at an inside point,E=0

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