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kinetic energy of a body is increased by 300%.What is the percentage increase in its momentum ??
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go for usual method instead... K=P^2/2m... after the increse in KE 4K=p'^2/2m divide the equations u get p/p'=1/2 p'=2p so % increase in p is p'-p/p* *100 = 2p-p/p*100 = p/p*100 = 100% |
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