IMPORTANT QUESTION : let ABC be a right angled triangle with BC =3 and AC=4. Let D be a point on the
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See, Draw The Triangle ABC and find its angles, ull find that they are 53.13 36.86 and 90 degrees....vertex B with 53.13 degree angle...now if u consider triangle BCD, u know B is 53.13 u knw BCD is 30 degree and the third angle will be 180 - other two....now u can use sine rule or cos rule to find length CD | |||||||||||||
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