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Suppose a pendulum of mass m1is suspended on the roof of a car. A light pin is attached to it and another pendulum of mass m2 is suspended from the pin. The car then starts with a constant accelaration. What are the angles @1 and @2 which the first and the second pendulum make with the vertical ?The answer goes like this.........From the FBD of the 2nd pendulum, by using lammi's theoremm2a/sin(180-@2) = T2/sin90 = m2g/sin(90+@2) tan@2 = a/g T2sin@2 = m2aT2cos@2 = m2gHere T2 = tension on the stringNow from the FBD of the 1st pendulumfor horizontal equilibriumm1a + T2sin@2 = T1sin@1 ......................(1)for vertical equilibriumm1g + T2cos@2 = T1cos@1 ............
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submitted by swashata4iit (880 m) on 17 Aug 2007 18:58:55 IST (7 comments 197 views)
