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METALLIC PARALLEL AND LARGE PLATE COMBINATION *For an isolated body total charge is always conserved*Net electrostatic field inside a conductor in absence of external force field (like gravitational, magnetic field ) is zero.The above concept can be used to find charge distribution on || plates. *Facing plates of the combination will carry equal and opposite charges always (to cancel electric field inside conductor)*If a particular plate/plates is/are grounded charge on it/them will NOT be conserved*The potential of conductor which is grounded become
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submitted by akku (1132 m) on 1 Feb 2008 16:56:32 IST (5 comments 154 views)
Questions: 1. An electrostatic charge of 21 u C is placed at a distance in air of 15 cmFrom a second charge. The force of attraction between the two charges is 26 N.A. Calculate the magnitude of the second charge.Sol) q1 = 21 u C = 21 x 10-6 C q2 = ?, F = 26N, R = 15cm = 0.15m Using F = q1 q2 / 4πεoR2 1/4πεo = 9 x 109 N-m2-C-2 Thus F = 9 x 109 q1 q2 / ( 0.15)2 or 26 = 9 x 109 q1 q2 / ( 0.15)2or 26 = 9 x 109 x 21 x 10-6 q2 / ( 0.15)2 = 1.89 x 105 q2 / ( 0.15)2 or q2 = 26 x ( 0.15)2 / 1.89 x 105 or q2 = 3.1 x 10-6 C = 3.1 μCB If the distance between t
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submitted by edison (4425 m) on 3 May 2008 17:35:42 IST (5 comments 177 views)
Electrostatics Examples You are advised to review the following examples. You should study them very closely and fully understand how they work. They all come from the preceding course, but the concepts will be used also in the present course. The problems have been laid out as follows: EG1 - forces and fields for single point charge EG2 - forces and fields for two point charges EG3 - 1-d motion in an electric field EG4 - 2-d motion in an electric field EG 1 Case Problem involving forces, electric potential energy, electric field and electric potential for two interacting point charges or charged spheres. Statement A cha
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submitted by Jyothi (752 m) on 10 Feb 2008 17:50:11 IST (7 comments 166 views)
Electric field To help visualize how a charge, or a collection of charges, influences the region around it, the concept of an electric field is used. The electric field E is analogous to g, which we called the acceleration due to gravity but which is really the gravitational field. Everything we learned about gravity, and how masses respond to gravitational forces, can help us understand how electric charges respond to electric forces. The electric field a distance r away from a point charge Q is given by: Electric field from a point charge : E = k Q / r2 The electric field from a positive charge points away from the charge; the electric field from a negative c
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submitted by johri_anshuman (1176 m) on 27 Sep 2007 22:27:28 IST (9 comments 225 views)
Electrostatics................. Electrostatics The fundamental equations of electrostatics are linear equations, (SI units), (Gaussian units). The principle of superposition holds. The electrostatic force on a particle with charge q at position r is F=qE(r). . f is the electrostatic potential. Important formulas: The field at r due to a point charge at r?: (Omit the factor to obtain the corresponding expressions in Gaussian units.) The field of a charge distribution: (We consider volume, surface, and line charge distributions and point charges.) Th
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submitted by rakesh61 (1884 m) on 25 Aug 2007 19:48:44 IST (7 comments 218 views)
Electrostatics Examples You are advised to review the following examples. You should study them very closely and fully understand how they work. They all come from the preceding course, but the concepts will be used also in the present course. The problems have been laid out as follows: EG1 - forces and fields for single point charge EG2 - forces and fields for two point charges EG3 - 1-d motion in an electric field EG4 - 2-d motion in an electric field EG 1 Case Problem involving forces, electric potential energy, electric field and electric potential for two interacting point charges or charged spheres. Statement A cha
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submitted by Jyothi (752 m) on 22 Apr 2007 17:05:27 IST (21 comments 511 views)
ELECTROSTATIC MATERIALS GLASS ROD , ROUNDED ENDS , 300 X 12 MM. EBONITE ROD , ROUNDED ENDS , 300 X 18 MM. HALF BRASS , HALF GLASS ROD , 300 X 12 MM. HALF BRASS , HALF EBONITE ROD , 300 X 12 MM. RUBBING CLOTH. Prod ID: EM-5201 + SIZES GOLD LEAF ELECTROSCOPE METAL CASE ,LID FINGER RIBS FOR REMOVAL , WITH EARTHING SOCKET AND SCALE WITH GLASS SIDES TO SEE THROUGH. Prod ID: GLE-5202 ELECTROSTATICS KIT FOR STUDENTS TO INVESTIGATE MANY ASPECT OF ELECTROSTSTIC FORCES. KIT COMPRISES : 1- ELECTROSCOPE. .... 1- PLATED WIRE HOOK. 2- POLYTHENE TIL
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submitted by Jyothi (752 m) on 28 Mar 2007 12:10:08 IST (1 comments 118 views)
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