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A bar made from an unknown but homogeneous elastic material is tested in tension at constant strain rate. The gauge length and diameter of the bar are 100 mm and 10 mm respectively. The force-extension graph resulting from the test is linear until the bar fractures suddenly at a load of 2.23 kN, and the extension at this point is 2.233 mm. Just before fracture a reduction of 0.9% in the bar’s diameter was measured. Determine: (i) the fracture stress;Sol) Stress = Force / AreaForce = 2.23kN = 2230 N, Radius R = 5mm = 5 x 10-3 mArea = π R2 = 3.14 x (5 x 10-3)2 = 7.85 x 10-5 m2Fracture Stress = 2230 / 7.85 x 10-5
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submitted by edison (4219 m) on 3 May 2008 17:32:41 IST (0 comments 66 views)
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