Future Experts come here and share their knowledge base and concepts with each other. Every article submitted is reviewed by experts. Nickels are awarded to articles in terms of authenticity, relevance, clarity and presentation.
Hi Guys ,
I am posting some great and useful tips and tricks with which you can save precious time in exams by minimizing written calculations . These tricks are based on vedic Mathematics . I hope you find them useful .
Trick 1 : Multiply any two numbers from 11 to 20 in your head.
Take 15 x 13 for example..Place the larger no. first in your mind and then do something like this Take the larger no on the top and the second digit of the smaller no. in the bottom.
15
3
The rest is quite simple. Add 15+3 = 18 . Then multiply 18 x 10 = 180 ...
Now multiply the second digit of both the no.s (ie; 5 x 3 = 15) Now add 180 + 15
Here is the answer 180 + 15 = 195 .
Thin
more ...
submitted by gauravthecool (12 m) on 4 Oct 2008 20:19:37 IST (5 comments 175 views)
check out what i discovered:volume of a sphere = 52% * (the volume of a cube having edge = the diameter of the sphere) let us say we have sphere of radius = r volume= 4/3*22/7* (r3) vol of cube of edge= (2r)3vol(sphere) *100%=4/3*22/7*r3*100% = 4*22*100%= vol(cube) 8r^3 3*8*7 =52.380952380952380952380952380952%~ 52.4%therefore the vol of the sphere of diamete
more ...
submitted by vagee (133 m) on 2 May 2007 20:01:47 IST (5 comments 335 views)
1.Coefficient of xm in the expansion of {axp + b/xq}n is the coefficient of Tr+1 where r=np-m/p+q to get the independent term of the above expansion put m=0 2.The coefficient of xn-1 in the expansion of (x-1)(x-2)(x-3).....(x-n) is -n(n+1)/2. 3.The coefficient of xn-1 in the expansion of (x+1)(x+2)....(x+n) is n(n+1)/2. 4.If the coefficients of rth,(r+1)th,(r+2)th terms of (1+x)n are in A.P. then (n-2r)2=n+2 5.The rth term from the end of (1+x)n is the (n-r+2)th term from the beginning 6.Sum of the coefficients of (ax+by)n is (a+b)n
more ...
submitted by sowmya111 (253 m) on 31 May 2007 22:28:21 IST (14 comments 650 views)
DETERMINANTS:- 1) If A is a square matrix of order n then i) I Adj A I = IAIn-1 ii) Adj(AdjA) = IAIn-2A iii)(AdjA)-1 = A/IAI = Adj(A-1) 2)For any scalar K , Adj(KA) = Kn-1AdjA 3) For a non-singula
more ...
[ 1
]
submitted by sowmya111 (253 m) on 1 Jun 2007 14:55:05 IST (16 comments 452 views)
A few methods for speed:When performing any of these multiplication algorithms, the multiplier should have as many zeroes prepended(prefixed) to it as there are digits in the multiplicand. This will provide room for any carrying operations. For instance, when multiplying 366 × 7, add one zero to the front of 366 (write it "0366"); when multiplying 985 × 12, prepend two zeroes to 985 ("00985"). Each digit but the last, including the prepended zeroes, has a neighbor, i.e., the digit on its right.To multiply by 12: Starting from the rightmost digit, double each digit and add the neighbor. This gives one digit of the result. If the answer is greater than 1 digit simply
more ...
submitted by vagee (133 m) on 31 May 2007 16:41:09 IST (3 comments 509 views)
We all know the standard formulas for range, height and time of flight of a projectile. Consider a problem like thisA particle projected obliquely at 45 deg has a range of 16m. Find the maximum height reached by the particle.Standard procedure:Write the formula for RangeEvaluate u.Find H.Time taken: 2 minLets do summa new.R = u2 sin2/ gH = u2 sin2 / 2gR/H = 4/tan4H = RtanUse this relation4H = 16 tan45H = 4Time taken :5 sYou get the idea. Similarly by doing R/T2 , H/T2 we get the following set of formulas4H = RtanRtan =(1/2)gT2 H = (1/8)gT2 Now try solving these problems:1. The range of a particle thrown at 45 deg is 8m. Find the time of flight.2. The maximum
more ...
submitted by elessar_iitkgp (2230 m) on 19 May 2007 10:11:54 IST (0 comments 503 views)
