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| #
| Voter
| Points
| Post
| Rate Date
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| 1 |
hemang |
 |
18!+1=0(mod 23) |
10 Dec 2011 10:19:33 IST |
| 2 |
Sambit Senapati |
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quadratic equations |
22 Sep 2011 13:31:11 IST |
| 3 |
jagdish singh |
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showthat the roots of the equation (p^4+q^4)x^$+4pqrsk+r^4+s^4=0 can not be different if real |
27 Jul 2011 23:47:27 IST |
| 4 |
hemang |
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prove that for any three real distinct numbers, a , b and c when a+b+c = 1
(1+a)(1+b)(1+c) > 8(1-a) |
18 Jul 2011 09:44:41 IST |
| 5 |
MAYANK KUMAR JHA |
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the number of real roots of the equation (x^2 + 2x)^2 - (x + 1)^2 - 55 =0 is a)2 b)1 c)4 d)none of t |
18 Jul 2011 09:34:08 IST |
| 6 |
Aakash Verma |
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the number of real roots of the equation (x^2 + 2x)^2 - (x + 1)^2 - 55 =0 is a)2 b)1 c)4 d)none of t |
17 Jul 2011 22:10:00 IST |
| 7 |
jagdish singh |
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the number of real roots of the equation (x^2 + 2x)^2 - (x + 1)^2 - 55 =0 is a)2 b)1 c)4 d)none of t |
17 Jul 2011 19:51:44 IST |
| 8 |
spiderman |
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Find all triangular numbers that are perfect squares.
|
16 Jul 2011 23:59:34 IST |
| 9 |
MAYANK KUMAR JHA |
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Find all triangular numbers that are perfect squares.
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16 Jul 2011 23:54:44 IST |
| 10 |
jagdish singh |
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show that there is no real number k,for |
14 Jul 2011 09:25:18 IST |
| 11 |
arna ghosh |
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The remainder when 2+[1!+2(2!)+3(3!)+..........+10(10!)] is divided by 11! is |
14 Jan 2011 18:45:03 IST |
| 12 |
jagdish singh |
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The remainder when 2+[1!+2(2!)+3(3!)+..........+10(10!)] is divided by 11! is |
14 Jan 2011 15:04:27 IST |
| 13 |
jagdish singh |
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the series is
1,2,2,3,3,3,4,4,4,4,.....
find 2000th term |
6 Jan 2011 19:03:55 IST |
| 14 |
jagdish singh |
|
the series is
1,2,2,3,3,3,4,4,4,4,.....
find 2000th term |
6 Jan 2011 19:03:52 IST |
| 15 |
jagdish singh |
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Q1) How many real solutions of the following equation are possible:6x2+77[x]+147=0 where [x] is GIF. |
6 Jan 2011 19:03:27 IST |
| 16 |
arna ghosh |
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IF 1+3+5+7+9+11+13+15+17+19=100 HOTE HAIN TO INME SE WO 5 NO. KOUN SE HAIN JINKA TOTAL 50 MILEGA. PL |
5 Jan 2011 12:35:53 IST |
| 17 |
. |
|
if a, b and c are in A.P series then prove that a^3+4b^3+c^3=3b(a^2+c^2) |
25 Dec 2010 11:16:35 IST |
| 18 |
. |
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if a, b and c are in A.P series then prove that a^3+4b^3+c^3=3b(a^2+c^2) |
25 Dec 2010 11:16:26 IST |
| 19 |
. |
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The equation ?(x+1) - ?(x-1) = ?(4x-1) has (IIT 97) a) no solution b) 1 solution c) 2 s |
25 Dec 2010 11:14:51 IST |
| 20 |
yaswanth kumar basava |
|
SETS |
20 Dec 2010 16:50:02 IST |
| 21 |
keytone |
|
SETS |
17 Dec 2010 23:42:10 IST |
| 22 |
Amanpreet Singh Lakshya Ko Hr Haal Me Paana Hai.. |
|
RMO 2008 FIRST ROUND |
16 Dec 2010 09:09:04 IST |
| 23 |
sandeep |
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f(x) f'(x) f''(x)>0 for all x belonging to R. Prove that f(x) is strictly increasing. |
15 Dec 2010 19:07:24 IST |
| 24 |
ayush |
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RMO MATHS OLYMPIAD 2011 |
8 Dec 2010 21:59:12 IST |
| 25 |
Amanpreet Singh Lakshya Ko Hr Haal Me Paana Hai.. |
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RMO MATHS OLYMPIAD 2011 |
8 Dec 2010 10:20:48 IST |
| 26 |
abhishek |
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plz reply!!!! if sinx ,siny are roots of equation a(sinz)^2+bsinz +c=0 & sinx+2siny=1 th |
5 Dec 2010 20:20:23 IST |
| 27 |
jagdish singh |
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With proof determine the no.of pairs (m,n) so that 3^m+2^n is the square of an integer. |
1 Dec 2010 12:23:57 IST |
| 28 |
jagdish singh |
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The equation ?(x+1) - ?(x-1) = ?(4x-1) has (IIT 97) a) no solution b) 1 solution c) 2 s |
1 Dec 2010 11:53:59 IST |
| 29 |
rahulmishra |
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if a,b and c are in A.P series then show that 1/(b^1/2+c^1/2), 1/(c^1/2+a^1/2) and 1/(a^1/2+b^1/2) |
29 Nov 2010 21:58:03 IST |
| 30 |
IIT ROCKER |
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if a, b and c are in A.P series then prove that a^3+4b^3+c^3=3b(a^2+c^2) |
29 Nov 2010 18:34:07 IST |
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